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We now develop quantitative measures for the hardware used for le storage This will provide parameters to use when evaluating alternate le organizations The parameters used in this book are oriented mainly toward disk type devices, but equivalent parameters can be obtained for other types of storage hardware We will capture the salient features of a wide variety of hardware and hardware oriented system choices with half a dozen parameters, summarized in Table 2-5 Some assumptions about the operation and use of the devices are made to simplify those parameters These have to be veri ed before building actual systems Di erent types of storage hardware need di erent assumptions To access some item of data, located at some known storage position, requires operations which cause an access delay This delay is called the random-access time It is based on the assumptions that the position of the data to be accessed and the initial position of the access mechanism are randomly distributed over the disk The assumption of randomness permits the estimation of the average time to reach a speci c known position The randomaccess time is the most critical parameter of storage device performance The term is not particularly felicitous, since the access to data is certainly not random The apparent randomness occurs because data are retrieved or stored in a sequence which is not determined by the device The random-access time is broken down into two constituents, seek time and latency The former refers to the positioning delay, for instance, the movement of the head mechanism of a disk, and latency is the rotational delay incurred until the data can be read The time required for the subsequent reading or writing depends on the size of the block of data being transferred and on the data-transfer rate of the hardware So, before proceeding with an analysis of the time needed to get the data, we will present how the hardware organizes the data into blocks.

Example A-40. One solution to Exercise 14-3 (continued)

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As can be seen in Table 2-1, the capacity of a track can be quite large Copying such a large quantity of data into memory can take a long time and much memory space It is hence common to divide a track into a number of blocks A block becomes the unit of data being transferred The division of a track into blocks may be implemented completely by hardware; such hardware units are termed sectors There will be a xed number of sectors, typically 10 or 16 per track, each capable of holding a xed number of characters In other disk units a track can be divided into sectors by a software Formatting software, provided with an operating system, writes markers onto the disk to de ne the block boundaries These markers are recognized by the hardware during normal read or write operations This division of a track into xed blocks by formatting is sometimes called soft sectoring, and the alternative devices are said to use hard sectoring If the size of a hard sector is inconveniently small, it is best to routinely use a number of sectors together as one block If soft sectoring is not supported by hardware, system software may yet divide data received from a track into smaller units, so that a reasonable block size is obtained In any case the block, be it composed of

{ return "My name is " + this.name + ", I weigh " + this.weight + ", and I am a " + this.Breed; } } public class Cat : Animal { public Cat(int weight, string name) : base(weight, name) { } public override void Speak( ) { Console.WriteLine("Meow"); } public override void Move( ) { Console.WriteLine("Run, tumble, nap."); } public override string ToString( ) { return "My name is " + this.name + ", I weigh " + this.weight + ", and I know how to purr!"; } public void Purr( ) { Console.WriteLine("Purrrrrrrrrrrrrrrrrrrrrrrrrr\n"); } } public class Tester { public void Run( ) { Console.WriteLine("Adding in the order: Milo, Shakespeare, Allegra, Dingo, Brandy"); Stack<Animal> myStackOfAnimals = new Stack<Animal>( ); myStackOfAnimals.Push(new Dog(72, "Milo", "Golden")); myStackOfAnimals.Push(new Cat(12, "Shakespeare")); myStackOfAnimals.Push(new Cat(10, "Allegra")); myStackOfAnimals.Push(new Dog(50, "Dingo", "mixed breed")); myStackOfAnimals.Push(new Dog(20, "Brandy", "Beagle")); Queue<Animal> myQueueOfAnimals = new myQueueOfAnimals.Enqueue(new Dog(72, myQueueOfAnimals.Enqueue(new Cat(12, myQueueOfAnimals.Enqueue(new Cat(10, myQueueOfAnimals.Enqueue(new Dog(50, myQueueOfAnimals.Enqueue(new Dog(20, Queue<Animal>( ); "Milo", "Golden")); "Shakespeare")); "Allegra")); "Dingo", "mixed breed")); "Brandy", "Beagle"));

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